6r^2+7r-2=0

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Solution for 6r^2+7r-2=0 equation: 



6r^2+7r-2=0

a = 6; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·6·(-2)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{97}}{2*6}=\frac{-7-\sqrt{97}}{12}
$


$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{97}}{2*6}=\frac{-7+\sqrt{97}}{12}
$

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